(2x^2+7x-10)/(2x-3)

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Solution for (2x^2+7x-10)/(2x-3) equation:


D( x )

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in (-oo:3/2) U (3/2:+oo)

(2*x^2+7*x-10)/(2*x-3) = 0

2*x^2+7*x-10 = 0

2*x^2+7*x-10 = 0

DELTA = 7^2-(-10*2*4)

DELTA = 129

DELTA > 0

x = (129^(1/2)-7)/(2*2) or x = (-129^(1/2)-7)/(2*2)

x = (129^(1/2)-7)/4 or x = (-(129^(1/2)+7))/4

(x+(129^(1/2)+7)/4)*(x-((129^(1/2)-7)/4)) = 0

((x+(129^(1/2)+7)/4)*(x-((129^(1/2)-7)/4)))/(2*x-3) = 0

( x+(129^(1/2)+7)/4 )

x+(129^(1/2)+7)/4 = 0 // - (129^(1/2)+7)/4

x = -((129^(1/2)+7)/4)

( x-((129^(1/2)-7)/4) )

x-((129^(1/2)-7)/4) = 0 // + (129^(1/2)-7)/4

x = (129^(1/2)-7)/4

x in { -((129^(1/2)+7)/4), (129^(1/2)-7)/4 }

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